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Math Forum » Discussions » Math Topics » geometry.pre-college.independent

Topic: analytic math/geometry
Replies: 1   Last Post: Oct 30, 2007 8:14 AM

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Being

Posts: 1
From: Md
Registered: 10/29/07
analytic math/geometry
Posted: Oct 29, 2007 11:15 AM
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There is a straight line which keep getting new "ends" and creating new segments. First, it has 2 then 3 ends,4, 5 6 etc. As you advance adding new ends, the number of segments icreases in a larger number than the number of ends. The first 2 is only 1 segment, when it's 3 is 3 segments, when it's 4 it's 6 segments, with 5 it's 10 segments, etc.
I figure that the first term of the conjecture is n-1 when "n" is the number of ends.
For instance:
for 2 ends: n-1 = 1
For 3 ends: (n-1) + 1 = 2 +1 = 3
for 4 ends: (n-1) + 2 + 1 = 6
for 5 ends: (n-1) + 3 + 2 + 1 = 10
and so on and so forth. Every time you increase the number of ends by one, you need to add the new number (n-1) plus the previous number of segments.
The question is to design the abbreviated form to solve just by giving the number of ends.
A second question is add all the "odd" number of ends. In this formula.
Thank you!

Math Being


Date Subject Author
10/29/07
Read analytic math/geometry
Being
10/30/07
Read Re: analytic math/geometry
BobMcK

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