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Topic: Birthday Problem Qualms
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Posts: 1
Registered: 12/16/07
Birthday Problem Qualms
Posted: Dec 16, 2007 12:42 AM
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Well, I was just googling some math puzzles to do (how nerdy,) but anyways... I came across this one:
Now, the question poses something along the lines of "how many students would need to be in a class in order for the probability of at least 2 to have the same birthdays be >= 50%." Now, I view this as a binomial distribution. let X = the event that 2 or more students have the same birthday. P(X >= 2) = E[(n over k)(p^k*(1-p)^(n-k))] where k = {2,3,4,...n) and n = class size. Formula can be found here:

First find the probability 2 or more students have the same birthday of a single day, say January 1st.
Suppose p = the probability of a student having a birthday on a single day of the year: 1/365 ~ .0027
n = class size = unknown variable
k = {2,3,4...n)
In order to consider all days of the year, we multiply the P(X >= 2 | day is January 1st) * 365.
Now if we just brute force this, plugging in 23 for class size (as suggested) gives you a probability of .6671, much higher than 50%. The get the closest value, 20 should be defined as n, giving you a probability of .5037.

Is there anything wrong with my thinking or calculations?

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