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Topic: P(m,n)=C(m,n)*p^m*q^(n-m) generalization
Replies: 4 Last Post: Feb 11, 2009 5:46 PM

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maxim

Posts: 2
From: moscow
Registered: 2/9/09

P(m,n)=C(m,n)*p^m*q^(n-m) generalization
Posted: Feb 9, 2009 11:24 AM

Plain Text

how to generalize formula P(m,n)=C(m,n)*p^m*q^(n-m) if random variables are correlated (assume ro=const)?

Date

Subject

Author

2/9/09

P(m,n)=C(m,n)*p^m*q^(n-m) generalization

maxim

2/9/09

Re: P(m,n)=C(m,n)*p^m*q^(n-m) generalization

almost

2/9/09

Re: P(m,n)=C(m,n)*p^m*q^(n-m) generalization

Stephen J. Herschkorn

2/9/09

Re: P(m,n)=C(m,n)*p^m*q^(n-m) generalization

quasi

2/11/09

Re: P(m,n)=C(m,n)*p^m*q^(n-m) generalization

bishop128@gmail.com