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Re: [apcalculus] net area vs total area
Posted:
Mar 3, 2009 11:32 AM


A sample of comments on net (signed) area Calculus I, Jerrold Marsden and Alan Weinstein, Section 4.3, The Definition of the Integral, page 215 ... The integral of a function is a "signed" area. ... Calculus in Context: The Five College Calculus Project, James Callahan, Kenneth Hoffman, et al., Chapter 6, The Integral, page 339 ... SIgned Area There is a way to simplify the geometric interpretation of an integral as area. It involves introducing the notion of signed area, by analogy with the notion of signed length. ... Calculus from Graphical, Numerical, and Symbolic Points of View, Arnold Ostebee and Paul Zorn, Chapter 5, The Integral, page 342 ... Signed Area In this chapter it is often convenient to consider signed area as opposed to area in the everyday sense. The adjective "signed" means that all areas below the xaxis counts as negative. ... Calculus: An Integrated Approach to Functions and Their Rates of Change, R. Gottlieb, Section 22.1, page 714 ... When using areas to represent net changes, we will use the idea of "signed area"  areas are positive or negative, depending on whether the region lies above or below the horizontal axis. ... In a message dated 3/2/2009 1:23:36 P.M. Eastern Standard Time, dwilliam@craneisd.com writes:
My class was evaluating the definite integral of 3 up to 1 int ( x^3 + x + 6) dx. The answer, according to the key and my calc was 12. So far, no problem. One of my students stated that if we accept the premise that an integral is the measure of area, sum of Reimann sums etc., then shouldn't the real answer be 14.872 as this represents the abs area of each of the sections when it is graphed? I suggested that the definite integral was also thought of as an accumulation of rates of change. The problem is analogous to the issue of displacement vs total distance traveled.
I am not comfortable with this analogy. Must we assume net accumulation of change or, must we assume total area? Is the distinction between net vs total area always made clear on the AP exam?
What would be a more effective way to explain this than the way I did using displacement vs total distance? ==== Course related websites: http://apcentral.collegeboard.com/calculusab http://apcentral.collegeboard.com/calculusbc  To unsubscribe click here: http://lyris.collegeboard.com/read/my_forums/?forum=apcalculus To change your subscription address or other settings click here: http://lyris.collegeboard.com/read/my_account/edit
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