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Topic: [ap-calculus] Introducing the Fundamental Theorem of Calculus
Replies: 2   Last Post: Mar 5, 2009 10:02 AM

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 BCrombie@AOL.COM Posts: 108 Registered: 12/8/04
Re: [ap-calculus] Introducing the Fundamental Theorem of Calculus
Posted: Mar 5, 2009 10:02 AM

The simplest case is paradigmatic.

Area-Slope Theorem I: The slope, m, of the graph of the area, A, under a
horizontal line, H, is the original horizontal line.

m( A( H ) ) = H.

Area-Slope Theorem II: The graph of the area, A, under the slope graph of a
straight line,SL, is a straight line parallel to the original straight line -
which means that the change in the area graph is equal to the change in the
original straight line across the same displacement.

A || SL

delta A = delta SL

In the general case, consider the area "under" the graph of a continuous
function f(x). The tangent line to the area graph is a linear area function. The
equation of the area graph's tangent line can be written in point-slope
form: AT(x)=m(x-a)+A(a). The area-slope term of that tangent line, by that I
mean the term m(x-a), corresponds to a rectangle of base (x-a) and height m.
Since the linear component of the area function is produced by the constant
component of the graph f(x), the slope is equal to the height of the function,
f(a).

So at each point x=a, the slope of the tangent line to the area graph is the
height of the original function at the specified point, f(a).

I leave it to others to dot all the "i"s and cross all the "t"s.

Bill Crombie

In a message dated 3/4/2009 9:05:52 A.M. Eastern Standard Time,
rexboggs5@optusnet.com.au writes:

Does anyone have a neat way of introducing/teaching this topic? The
approach in my text is quite
long and I think there must be a better, more intuitive way.

Cheers

Rex

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Course related websites:
http://apcentral.collegeboard.com/calculusab
http://apcentral.collegeboard.com/calculusbc
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Course related websites:
http://apcentral.collegeboard.com/calculusab
http://apcentral.collegeboard.com/calculusbc
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