In:= LaplaceTransform[InverseLaplaceTransform[s*Exp[(-a)*Sqrt[s]], s, t], t, s] Out= E^(-a Sqrt[s]) s
The second is the exact function in the argument. The first does not process the three conditions of the LT of BesselI[1,t].
On Jun 13, 2009, at 3:01 AM, Sid wrote:
> Dear MathGroup, > > I am currently using Version 6 and have found that > > InverseLaplaceTransform[LaplaceTransform[BesselI[1,t],t,s],s,t] > > yields, after tidying up, 1/2 BesselI[1,t]. > > > Also, > > LaplaceTransform[InverseLaplaceTransform[s*Exp[(-a)*Sqrt[s]], s, t], > t,s] > > gives ((1/2)*s)/E^(a*Sqrt[s]) . > > > Do members have the same problem with Version 7 ? > > Is it I who am missing something here ? > > > Thanks for your help. > > Cheers > > Sid >