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Math Forum » Discussions » Software » comp.soft-sys.matlab

Topic: bilinear transformation
Replies: 3   Last Post: Nov 7, 2009 1:15 PM

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Ana

Posts: 9
Registered: 11/3/09
bilinear transformation
Posted: Nov 4, 2009 5:33 PM
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hi ,
If i understood correctly bilinear transformation is used in order to transform from s domain to the z domain. Now why then when using;
example;

fp = 2e03;
fs = 20e03;
s = tf('s');
num = 1;
den = (s^2 + 1.414*s + 1); % butterworth 2nd order
[numd,dend] = bilinear(num,den,fs,fp)
it is telling me that function rdivide cannot be classified by tf, i guess numd and dend will give basically the transfer function in the zdomain.

Any ideas highly appreciated.Thanks beforhand

Ana

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