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Topic: Union of probabilities
Replies: 2   Last Post: Jan 12, 2010 7:23 PM

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Steve B

Posts: 16
Registered: 12/8/09
Re: Union of probabilities
Posted: Jan 12, 2010 7:23 PM
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> I thought over and realized that, the probability of
> "picking up at least one eligible red ball after
> drawing balls from B1, B2 and B3" can be re-phrased
> as "1 - probability of picking up no eligible red
> balls".
> Thus, the probability of picking at least one
> eligible red ball would be :
> 1 -
> {(R1-r1+G1+B1)(R2-r2+G2+B2)(R2-r2+G2+B2)/(R1+G1+B1)(R2
> +G2+B2)(R3+G3+B3)}
> Is this correct ?


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