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Steve B
Posts:
16
Registered:
12/8/09


Re: Union of probabilities
Posted:
Jan 12, 2010 7:23 PM


> I thought over and realized that, the probability of > "picking up at least one eligible red ball after > drawing balls from B1, B2 and B3" can be rephrased > as "1  probability of picking up no eligible red > balls". > > Thus, the probability of picking at least one > eligible red ball would be : > > 1  > {(R1r1+G1+B1)(R2r2+G2+B2)(R2r2+G2+B2)/(R1+G1+B1)(R2 > +G2+B2)(R3+G3+B3)} > > Is this correct ?
Yes.



