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SMR
Posts:
1
Registered:
5/18/10


Is this possible: One to One functions from x=6 and Z=7
Posted:
May 18, 2010 10:16 PM


My curiosity lies in the lack of definition  I know that to be one to one there must be exactly one y for every x. However, in this case, the sets are not equal and one y will be left without an x. Does this negate the definition of one to one, or can you still have 6 one to one functions?
Thanks for the help!



