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Topic: 6 points in R3 conjecture
Replies: 3   Last Post: Jul 22, 2010 9:53 AM

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ou, janis

Posts: 1
Registered: 7/19/10
6 points in R3 conjecture
Posted: Jul 19, 2010 2:45 AM
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Take 6 points in 3D space in general position: no 3 in a line, no 3
forming a right angle, no 4 in a plane. Draw all 15 lines between them.
This will form 20 distinct triangles. (For each of the six points there
are ten pairs of other points, but the apparent 60 triangles are each
counted three times.) Each triangle can have at most one obtuse angle,
so the maximum number of obtuse angles in the whole figure, over all
such point sets, is 20.

Conjecture: the minimum number of obtuse angles over all 6-point sets in
3 dimensions is 2.

This has been established experimentally to a high degree of probability
by creating 28 million (so far) random 6-point sets and counting the
obtuse angles in each set. I do not know how to prove it, and I see no
way to find a counterexample except by trying additional millions of
point sets, which are not likely to turn up any.

I think this is a new problem, and I have other similar conjectures.

Steve Gray

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