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Difference in integral not understood
Posted:
Sep 6, 2010 12:49 AM



Hi
I am out of touch of maths for last 12 years and now reviving my math. I am getting two different answers for the same integral.
I= Integral (sinx)^2(cosx)dx
method1 If I proceed with (sinx)^2 = 1(cosx)^2, I endup with answer sinx((cosx)^4)/4)
method2 with method of substitution u=sinx and hence du=cosxdx so the answer is ((sinx)^3)/3
Since both the methods look correct me, I am unable to find reason for this difference. Can some one help me



