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Very tough geometry problem
Posted:
Nov 13, 2010 9:30 AM


Here is a very tough geometry problem Q.In quadrilateral ABCD , where AD,DC, CB and BA are sides, whereas AC and BD are diagonals. BC=AC.Angle BCA=x degree.Angle ABD=[30(x/2)] degree and angle BAD=150 degree. Find angle BDC.



