h.jones
Posts:
32
From:
uk
Registered:
2/21/08


SONNTAG! Symmetries of Nature 'n' Truth about Gravity(& Planck Units).
Posted:
Nov 23, 2010 12:44 PM


Symmetries are everywhere, all you have to do is look. In the area of symmetries between quantum and gravitational effects we can consider the age old remedy of multiplying a given formula by 1 or 1^2. One such formula we can consider is Einstein's equation for the deflection of starlight as it passes the Sun. The formula, including the factor of 2, is 4GM/Rc^2, where M is the Sun's Mass and R its Radius. We can multiply by 1^2, in this case M/Mxh/h which enlarges the formula to (h4GM^2)/(RMhc^2). This reassembles to: (h/RMc)(4GM^2)/ch. In the Planck unit formula where the Compton wavelength of the Planck mass is equal to its Schwarzschild Diameter, given that the full length of the structures are equal, then ch is equal to 4Gm^2, where small m is the Planck mass. Substituting for the above formula we have: (h/RMc)(GM^2)/Gm^2 which breaks down to (h/RMc)(M^2)/m^2=2x2.9697x10^3/ R. There are three elements here, firstly, h/RMc, which is the Compton wavelength of the Sun divided by Radius. If we make the Radius the Schwarzschild Radius at this point then we can consider the following: the Compton wavelength of the Sun has two functions in gravitational interactions and its function in this particular case is to represent the smallest angular deflection, including the tangent to the curve, that effects a passing light beam's flightpath during the period of one Planck unit of time. The Compton wavelength divided by R= 2.9697x10^3=3.7212x10^76 Radians. The second element, M^2/m^2 is the Planck frequency of the Schwarzschild Radius squared. The squaring of the frequency effects the total accelerative angular deflection and the said frequency squared is equal to 5.37452x10^75. Multiply this by 3.7212x10^76 radians and you get 2 radians. The third element shows 2x2.9697x10^3 which is twice Schwarzschild Radius. If we want get the outcome of the current Radius ot the Sun then we substitute with 6.9697x10^8 which gives 8.53366x106 Radians. Multiply this by 3600x57.3 and we get our 1.76 seconds of arc

