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Topic: SONNTAG! Symmetries of Nature 'n' Truth about Gravity(& Planck Units).
Replies: 24   Last Post: Mar 26, 2012 6:48 PM

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 h.jones Posts: 32 From: uk Registered: 2/21/08
SONNTAG! Symmetries of Nature 'n' Truth about Gravity(& Planck Units).
Posted: Nov 23, 2010 12:44 PM

Symmetries are everywhere, all you have to do is look. In the area of
symmetries between quantum and gravitational effects we can consider
the age old remedy of multiplying a given formula by 1 or 1^2. One
such formula we can consider is Einstein's equation for the deflection
of starlight as it passes the Sun. The formula, including the factor
of 2, is 4GM/Rc^2, where M is the Sun's Mass and R its Radius. We can
multiply by 1^2, in this case M/Mxh/h which enlarges the formula to
(h4GM^2)/(RMhc^2). This reassembles to:
(h/RMc)(4GM^2)/ch. In the Planck unit formula where the Compton
wavelength of the Planck mass is equal to its Schwarzschild Diameter,
given that the full length of the structures are equal, then ch is
equal to 4Gm^2, where small m is the Planck mass. Substituting for
the above formula we have:
(h/RMc)(GM^2)/Gm^2 which breaks down to (h/RMc)(M^2)/m^2=2x2.9697x10^3/
R. There are three elements here, firstly, h/RMc, which is the
Compton wavelength of the Sun divided by Radius. If we make the
Radius the Schwarzschild Radius at this point then we can consider the
following: the Compton wavelength of the Sun has two functions in
gravitational interactions and its function in this particular case is
to represent the smallest angular deflection, including the tangent to
the curve, that effects a passing light beam's flightpath during the
period of one Planck unit of time. The Compton wavelength divided by
The second element, M^2/m^2 is the Planck frequency of the
Schwarzschild Radius squared. The squaring of the frequency effects
the total accelerative angular deflection and the said frequency
squared is equal to 5.37452x10^75. Multiply this by 3.7212x10^-76
which is twice Schwarzschild Radius. If we want get the outcome of
the current Radius ot the Sun then we substitute with 6.9697x10^8
which gives 8.53366x10-6 Radians. Multiply this by 3600x57.3 and we
get our 1.76 seconds of arc

Date Subject Author
11/23/10 h.jones
11/28/10 h.jones
12/8/10 h.jones
12/14/10 h.jones
12/30/10 h.jones
1/8/11 h.jones
2/17/12 h.jones
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2/22/12 h.jones
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2/27/12 h.jones
3/17/12 haroldj.l.jones@gmail.com
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3/19/11 h.jones
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