h.jones
Posts:
32
From:
uk
Registered:
2/21/08
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Re: SONNTAG! Symmetries of Nature 'n' Truth about Gravity(& Planck Units).
Posted:
Feb 27, 2012 1:21 PM
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THE SCHWARZSCHILD RADIUS:
Nassim Haramein's theory of the proton having a discrete mass of
8.9x10^11kg is interesting because it exhibits some aspects of the
Schwarzschil/Compton opposites phenomena I have recently been mailing
about. The main difference being that the opposite of the proton has
a diameter equal to the proton's Compton wavelength of 1.32141x10^-15m
making its mass 4.45039x10^11kg not 8.9x10^11kg. Therefore, its radius
is half the wavelength and its Gm product 29.6906036. The theory seems
to suggest that the mass has turned itself inside out in some way.
There are some suggestions that can go some way to explain why.
In gravitational free fall onto a Schwarzschild surface measured in
Planck time units, the rate of fall is half the Compton length(of the
gravitating body)per Planck time unit. So in the case of the Sun the
rate of fall would be half the Compton length of the Sun per Planck
time unit by the falling object. But this rule only applies down to
and including a Planck sphere. After that the rule no longer
applies. The Schwarzschild radius of a proton is 2.483176x10^-54m.
Half its Compton wavelength is 6.60705x10^-16m, some 2.66072482x10^38
times bigger. If an object was subjected to this amount of
acceleration it would have to travel faster than light.
Clearly, a new set of rules is needed. What about relativistic
transfer? what about the primordial black holes that were abundant
after the Big Bang? These were estimated to be around the size of the
proton opposite. The surface g at the Planck limit is
1.109439913x10^51m, which must be equivalent to c. If the primordial
black hole's surface g exceeded this it would go into relativistic
meltdown or gravitational relativistic spacetime contraction. If
radius contracted so would surface area, so would length, so would
time.
A four dimension meltdown. For a 2.66x10^38 mass contraction we would
need a 4.038776x10^9 contraction rate to effect that.
The Rydberg energy is 2.179874166x10^-18J. We're not sure what the
proton nucleus poential is. What the nucleus does do, however, is
exert a force on the wave structure of another particle. The mass-
time equivalence of a wave can be whittled down to h/c^2 or
7.3725x10^-51kg. 2.95676257x10^32x7.3725x10^-51=2.17987x10^-18J.
2.95676257x10^32 is c^3 multiplied by the Rydberg constant.
So something in the nucleus is generating all that power,
2.95676x10^32.
In recent posts mention has been made of the constant 3.62994678 fom
the Gn model. If we take half the proton wavelength, 6.060705x10^-16m
and divide by 3.62884678 we get 1.82015064x10^-16m. If we divide this
into the Rydberg energy of 2.179874166x10^-18J we get the figure
1.1973731534x10^-2. This is the discrete Gm equivalence of the
nucleus. So our formula could be:
(1.1973731534x10^-2)(7.37250325x10^-51)/4.05049049x10^-35m=
2.179874166x10^-18J. The radius or distance, here, is measured by the
Planck radius. The situation.here, is nucleus/wave structure which
could be construed as zero separating distance. As nothing can be
considered smaller than the Planck radius it must be Planck.
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