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Topic: difference equation
Replies: 4   Last Post: Mar 5, 2013 3:03 AM

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vikas kumar

Posts: 1
Registered: 11/27/10
difference equation
Posted: Nov 27, 2010 5:18 AM
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how do we solve this difference equation :
y(n) + 1/2y(n-1) + 3/4y(n-2) = x(n)

where x(n)=(1/4)^n for all n>0
& y(-1)=4 , y(-2)=6

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