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Topic: A different geometry problem
Replies: 7   Last Post: Dec 13, 2010 10:06 AM

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Philippe 92

Posts: 44
Registered: 5/10/06
A different geometry problem
Posted: Dec 10, 2010 4:49 AM
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Hi,

It looks like it were a "Sujeet's" but it is a little different...

In a triangle ABC, a point P such as angle PAB = 30 deg,
angle PAC = 20 deg, angle PBA = 10 deg, angle __PCB__ = 70 deg.
Find the angle PBC.
So that there is only one solution, I add the following condition :
none of the triangles in the figure is isosceles.

This problem is different from the previous ones, as the given
data results into _two_ solutions.
One of them has some isosceles triangles and is then rejected by
the additional condition.

It seems however you have to find both solutions to know which one
is to be rejected !

Regards.



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