The Math Forum

Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.

Math Forum » Discussions » Math Topics » geometry.puzzles

Notice: We are no longer accepting new posts, but the forums will continue to be readable.

Topic: A different geometry problem
Replies: 7   Last Post: Dec 13, 2010 10:06 AM

Advanced Search

Back to Topic List Back to Topic List Jump to Tree View Jump to Tree View   Messages: [ Previous | Next ]
Philippe 92

Posts: 44
Registered: 5/10/06
A different geometry problem
Posted: Dec 10, 2010 4:49 AM
  Click to see the message monospaced in plain text Plain Text   Click to reply to this topic Reply


It looks like it were a "Sujeet's" but it is a little different...

In a triangle ABC, a point P such as angle PAB = 30 deg,
angle PAC = 20 deg, angle PBA = 10 deg, angle __PCB__ = 70 deg.
Find the angle PBC.
So that there is only one solution, I add the following condition :
none of the triangles in the figure is isosceles.

This problem is different from the previous ones, as the given
data results into _two_ solutions.
One of them has some isosceles triangles and is then rejected by
the additional condition.

It seems however you have to find both solutions to know which one
is to be rejected !


Point your RSS reader here for a feed of the latest messages in this topic.

[Privacy Policy] [Terms of Use]

© The Math Forum at NCTM 1994-2018. All Rights Reserved.