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Re: Geometry problem no.3
Posted:
Dec 29, 2010 4:04 PM


> Here is geometry problem no.3 : > Q.In a triangle ABC, point P is taken so that angle > PCB=x degree and angle PBC=30 degree.Find angle > BAP.It is given that angle ABC=[135(x/2)] degree and > angle ACB=30 degree.
Will you give an overall solution? Again, here's no solution. Angle BAP = x degrees, 0<x<30



