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Geometry problem no.4
Posted:
Dec 30, 2010 10:56 AM


Here is geometry problem no.4 : Q.In a triangle ABC , point P is taken so that angle ABP=(60+x) degree,angle PBC=30 degree, angle PCB=x degree and angle PCA=(602x) degree.Find angle BAP.
As, when x=10 or multiples of 10 degree, then sides and cevian can be seen as sides and diagonals of 18 gon.In the same way with suitable replacement of x, sides and cevians of this problem will become diagonals and sides of higher gons.For example 30gon, 24 gon , 60gon or 360gon. I am very bad in expressing myself, but this time I hope, I have made myself clear.



