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Derivation of the Sum of a Series
Posted:
Sep 23, 2001 6:43 PM


Hello All,
I need to derive the following.
The sum from i=1 to i=n of i^2. The result of the derivation should be [n(n+1)(2n+1)]/6.
A similar derivation for the sum from i=1 to i=n of i is the following
Let X= sum from i=1 to i=n of i
1 + n =n+1 2 + n1 =n+1 3 + n2 =n+1 n terms . + . =n+1 . + . =n+1 n + 1 =n+1 X + X =n(n+1)
Therefore, X=[n(n+1)]/2
Similarly, a derivation for the sum from i=1 to i=n of i^3 would be great.
If anyone knows how to do this, please EMail me at ea342@stern.nyu.edu
Thank You So Much, Eric

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