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Topic: Re: [mg5311] Single Problem
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BobHanlon@aol.com

Posts: 906
Registered: 12/7/04
Re: [mg5311] Single Problem
Posted: Nov 26, 1996 3:36 AM
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X = Sqrt[6 + Sqrt[6 + Sqrt[6 + Sqrt[6 + ...]]]]
X = Sqrt[6 + X]
X^2 = 6 + x
X^2 - x - 6 = 0
(X - 3) (X + 2) = 0
X = 3 and X = -2

The latter is an extraneous root. X = 3

In Mathematica this can be solved using either

Solve[X == Sqrt[6 + X], X]

or

FixedPoint[Sqrt[6. + #]&, Sqrt[6.]]

Bob Hanlon

FORWARDED MESSAGE:

Subj: [mg5311] Single Problem
Date: Sat, Nov 23, 1996 4:58 AM EDT
From: yelride@ibm.net
X-From: yelride@ibm.net (Redirley Matheus Santos)
To: mathgroup@smc.vnet.net

Hi everybody,

Who would like solve this problem ?

X is a Integer number
X = Sqr(6+(Sqr(6+(Sqr(6+Sqr(6+Sqr(...))))))) infinite Sqr of 6 inside
X = ?








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