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Topic: Re: [mg5313] Integrals of Erf via M3
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Andrei Constantinescu

Posts: 32
Registered: 12/7/04
Re: [mg5313] Integrals of Erf via M3
Posted: Nov 26, 1996 3:39 AM
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I think your problem lies in the error function which can't be computed
in an explicit form, this is why nobody can convince mathematica to do the

However if a-d are number you can do it numerically:

In[3]:= NIntegrate[Evaluate[ Exp[-x^2]Erf[2 x + 1] Erf[ 4 x - 1] ], {x,-Infinity,Infinity}]

Out[3]= 0.442036

a + andrei

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