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Re: [mg5313] Integrals of Erf via M3
Posted:
Nov 26, 1996 3:39 AM


I think your problem lies in the error function which can't be computed in an explicit form, this is why nobody can convince mathematica to do the computation.
However if ad are number you can do it numerically:
In[3]:= NIntegrate[Evaluate[ Exp[x^2]Erf[2 x + 1] Erf[ 4 x  1] ], {x,Infinity,Infinity}]
Out[3]= 0.442036
a + andrei



