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Topic: Re: [mg5339] Need help with solving problem
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Jens-Peer Kuska

Posts: 12
Registered: 12/7/04
Re: [mg5339] Need help with solving problem
Posted: Dec 1, 1996 11:21 PM
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> From Wed Nov 27 16:34:00 1996
> From: (Ingimar V\vlundarson)
> To:
> Subject: [mg5339] Need help with solving problem
> Content-Length: 399
> X-Lines: 24
> Can anyone help me with this problem?
> (4^x)+(2^x)-2=0
> Everyone can see that x=0 but:
> (4^x)+(2^x)-2=0 =>
> 2*(2^x)+(2^x)-2=0 =>

Yes ? really that are new kind of calculation rules.
I think

(4^x)== 2^(2x) ==2^x*2^x and You get

finaly one gets the correct solution
x-> I (Pi-I*Log[2])/Log[2]

Hope that helps

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