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Re: [mg5339] Need help with solving problem
Posted:
Dec 1, 1996 11:27 PM


At 06:47 AM 11/27/96 +0000, you wrote: >Can anyone help me with this problem? > >(4^x)+(2^x)2=0 > >Everyone can see that x=0 but: > >(4^x)+(2^x)2=0 => >2*(2^x)+(2^x)2=0 => THIS STEP IS NOT TRUE IT SHOULD BE 2*(2^(2*x1))+(2^x)2 >2y+y2=0 => ;(let y=2^x) WHICH MAKES THE REST WRONG >3y=2 => TRY IT IN MMA >y=2/3 => >2^x=2/3 => ;(let 2^x=y) >lg(2^x)=lg(2/3) => >x*lg(2)=lg(2/3) => >x=lg(2/3)/lg(2) Which is not true!!! > >Am I doing something wrong? > >Please Email an answer to: >ingimar.volundarson@mailbox.swipnet.se > >Thanx in advance! > > >



