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Topic:
[apcalculus] another problem
Replies:
7
Last Post:
May 3, 2011 5:09 PM




re:[apcalculus] another problem
Posted:
May 3, 2011 11:44 AM


The diameter of the semicircles, drawn from the xaxis to the line, will have a length equal to the yvalue of the line, .5x+4. Thus the radius of each semicircle is .25x+2. The area of each semicircle is then .5pi(.25x+2)^2.
The line has an xintercept of (8,0), so integrate .5pi(.25x+2)^2 from 0 to 8 to get approx 16.755.
HTH, Jason Waller Helix Charter HS San Diego, CA

The base of a solid is a region in 1st quadrant bounded by xaxis, yaxis and the line x+2y=8. Crosssections of the solid perpendicular to the xaxis are semicircles, what is the volume of the solid. Answer is 16.755I keep getting a much bigger answer. Any help???
Mark A Wise JBHS Mercersburg, PA ==== Course related websites: http://apcentral.collegeboard.com/calculusab http://apcentral.collegeboard.com/calculusbc  To search the list archives for previous posts go to http://lyris.collegeboard.com/read/?forum=apcalculus To unsubscribe click here: http://lyris.collegeboard.com/read/my_forums/ To change your subscription address or other settings click here: http://lyris.collegeboard.com/read/my_account/edit



