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Topic: An cyclic inequality
Replies: 6   Last Post: Jul 29, 2011 5:01 PM

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Dan Hoey

Posts: 172
Registered: 12/6/04
Re: An cyclic inequality
Posted: Jul 29, 2011 3:10 PM
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On 7/28/11 5:42 PM, quasi wrote:
> Presumably, the intended problem was as follows:
> Prove that if x,y,z are positive real numbers such that
> x + y + z = 3
> then
> (x+1)/(y^2+1) + (y+1)/(z^2+1) + (z+1)/(x^2+1)>= 3

It still fails when x=y=z=1.


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