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On PDEs [First Order Nonlinear]
Posted:
Sep 10, 2011 10:47 AM


ResentFrom: <bergv@illinois.edu> From: Anamitra Palit <palit.anamitra@gmail.com> Date: September 10, 2011 7:56:57 AM MDT To: "scimathresearch@moderators.isc.org" <scimathresearch@moderators.isc.org> Subject: On PDEs [First Order Nonlinear]
Let us consider the following partial differential equation:
[del_z/del_x]^2+[del_z/del_y]^2=1  (1) The general solution[you will find in the texts: http://eqworld.ipmnet.ru/en/solutions/fpde/fpde3201.pdf] is given by: z=ax+sqrt[1a^2]y+B; a and B are constants.(2) Now let me search for a solution in the form: z=axf(z)+sqrt[1a^2]y+ B del_z/del_x=axf'(z)del_z/del_x+af(z) del_z/del_y=sqrt[1a^2]+axf'(z)del_z/del_y
Substituting the above values into (1) we get [af(z)/[1axf'(z)] ]^2+(1a^2)/[1axf'(z)]^2 = 1 Or, a^2 [f(z)]^2+1a^2=[1ax f'(z)]^2  (3) If the above differential equation is solvable we should get a broader range of general values.Are we missing some solutions if the conventional general solution is considered? Now , the above equation[ie,(3) contains x. We write, z=F(x,y) For any particular value of z say, z=k, we have, k=F(x,y) Keeping x fixed at some arbitrary value we can obtain k be changing y only[I believe that this may be possible in most situations or in may situations]. [We could have achieved the same effect,i.e, getting z=k, by changing both x and y in some manner] So we may try to solve our differential equation[the last one(3)] by keeping x fixed at some arbitrary value. This will go in favor of my methodology.
Suppose we have only one local maximum for the entire range of our function z=F(x,y) at the point (x0,y0) . For this point, k=F(x0,y0) The value of k in this situation, will not be accessible for any arbitrary x. One has to use x=x0. To surmount this difficulty one may think of dividing the the domain of definition of the function F,into subdomains so that in any particular subdomain, the value of z may be accessible for an arbitrary x in that subdomain. [Rather we would look for a function,z=F(x,y), of this type]
On Boundary Conditions]
The general solution[relation (2) seems to be too restrictive with simple boundary conditions. We may consider a square domain: x=0,x=k,y=0,y=k [k: some constant] Let us take the line:x=k It is perpendicular to the xaxis If we use the value x=k in (2) ,then z changes linearly wrt y
The general solution[conventional one] talks of plane surfaces given by (2). I can always take small pieces of such surfaces and sew them into a large curved surface ,z=F(x,y).Along the boundary z may be a nonlinear function of x or y.
Alternatively: Along the line x=constant[=k],we have from (1), m(x=k,y)+[del_z/del_y]^2=1 Where m(x=k,y) represents the value of [del_z/del_x]^2 along the line x=k =>[del_z/del_y]=+Sqrt[1m(k,y)] or Sqrt[1m(k,y)]  (3)
Now we divide the line x=k into small strips[one may consider infinitesimal strips] each of length h [from y=0 to y=k] For one [or more ] strip we take the positive value[+Sqrt[1m]] in relation (3) and for some other[or others] we take the negative value [Sqrt[1m] in (3) As a result at the boundary x=k we may have a nonlinear function z=g(y) instead of a linear one as predicted by the conventional general solution.The linearity is produced by the change of sign and by changes in the value of m. This can change the whole picture of the problem



