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exp(log(1)) = 1 ???
Posted:
Sep 19, 2011 7:41 PM


I was playing around an alternate imaginary operator,
x = exp(log(1))
You can derive the following (assume i = sqrt(1) as usual)
x = exp(log(1) = exp(log(i^2)) take log of both sides log(x) = log(i^2) x = i^2 = 1
weird!



