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Topic: [math-learn] Question about unknown angle in a Parallelogram.
Replies: 8   Last Post: Oct 11, 2011 9:59 AM

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Jon Wilson

Posts: 56
Registered: 9/25/05
[math-learn] Re: Question about unknown angle in a Parallelogram.
Posted: Oct 11, 2011 1:30 AM
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att1.html (14.5 K)

Thanks, and I came to the same conclusion in regard to the range of values for X.

You feedback and confirmation of the problem are appreciated.

And, while everyone benefits from an occasional review, I rarely find it necessary to make inquiries of the type, and even less frequently in the evening. For what ever reason (mostly fatigue) it just stumped me.

Never the less, I do appreciate the input.





--- In math-learn@yahoogroups.com, Ze'ev Wurman <zeev@...> wrote:
>
> Any quadrangle has its sum of interior angles=360 (trivial to prove).
> Hence, your fourth angle (across from 180-x) is 360-2x-(180-x)=180-x. As
> the opposing angles are identical, it is, indeed, a parallelogram. (you
> called it a "parallelogram" but you said it is constructed out of "4
> intersecting lines" -- you did not say they were two sets of parallel
> lines. If you actually knew it was a parallelogram to begin with, you
> could have simply used that to find that the angle opposite (180-x) is
> the same as 180-x.)
>
> As to the actual value of X (and 180-x)? Anything greater than 0 and
> less than 180 will work. Hence X (smile).
>
> It really seem you could benefit from a review of your geometry.
>
> On 10/10/2011 9:04 PM, jjaywilson2004 wrote:

> >
> > I beg your pardon, I never said it was homework.
> >
> > --- In math-learn@yahoogroups.com
> > <mailto:math-learn%40yahoogroups.com>, Ze'ev Wurman <zeev@> wrote:

> > >
> > > This list is not a homework assistance hot line ... a hint was more

> > than
> > > enough.
> > >
> > > On 10/10/2011 8:44 PM, jjaywilson2004 wrote:

> > > >
> > > > Okay... then how would I solve for the unknown?
> > > >
> > > > Jon
> > > >
> > > > --- In math-learn@yahoogroups.com

> > <mailto:math-learn%40yahoogroups.com>
> > > > <mailto:math-learn%40yahoogroups.com>, Ze'ev Wurman <zeev@> wrote:
> > > > >
> > > > > Exterior angle theorem does not apply to quadrangles ...

> > > >
> > >
> > >
> > >
> > > [Non-text portions of this message have been removed]
> > >

> >
> >

>
>
>
> [Non-text portions of this message have been removed]
>






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