
Re: constructing indices
Posted:
Oct 23, 2011 1:32 PM


On Oct 23, 11:16 am, "Nasser M. Abbasi" <n...@12000.org> wrote: > On 10/23/2011 11:44 AM, raj wrote: > > > > > > > > > > > Hello all, > > To the following indices order, how the third indices work? > > > (1, 1, 1) > > (2, 1, 1) > > (3, 1, 2) > > (1, 2, 2) > > (2, 2, 3) > > (3, 2, 3) > > (1, 3, 4) > > (2, 3, 4) > > (3, 3, 5) > > (1, 4, 5) > > (2, 4, 6) > > (3, 4, 6) > > (1, 5, 7) > > (2, 5, 7) > > (3, 5, 8) > > (1, 6, 8) > > (2, 6, 9) > > (3, 6, 9) > > > Appreciate your help. > > R > > ...... > > Not sure what you mean by " how the third indices work?". > > Work in what sense? > > I think of a 3D matix as a book. > 2D matrix as page in the book. > and 1D matrix as a row or a column on page. > > So, (3, 1, 2) means the third line, in the first column on the second page of the book. > and (3, 6, 9) means the third line, in the 6th column on the 9th page of the book. > > and so on > > Nasser
Thanks Nasser. I have the code: p = 0; for j = 1:3; for i = 1:3; p = p+1; if (mod(p,2)==1) [i j p] else [i j p1] end end end
It produces (1, 1, 1) (2, 1, 1) (3, 1, 3) (1, 2, 3) (2, 2, 5) (3, 2, 5) and so on.
But I want to get the following. (1, 1, 1) (2, 1, 1) (3, 1, 2) (1, 2, 2) (2, 2, 3) (3, 2, 3) and so on.
Thanks, R

