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Please factor this sextic, thank you.
Posted:
Mar 27, 2012 12:40 AM
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Hello.
Does this cute sextic polynomial in x
(8*b*e^2 - 4*c*d*e + d^3)*x^6 + 2*(16*a*e^2 + 2*b*d*e - 4*c^2*e + c*d^2)*x^5 + 5*(8*a*d*e - 4*b*c*e + b*d^2)*x^4 + 20*(a*d^2 - b^2*e)*x^3 - 5*(8*a*b*e - 4*a*c*d + b^2*d)*x^2 - 2*(16*a^2*e + 2*a*b*d - 4*a*c^2 + b^2*c)*x - 8*a^2*d + 4*a*b*c - b^3
split into rational factors if
64*a^3*e^3 - 48*a^2*b*d*e^2 - 64*a^2*c^2*e^2 + 48*a^2*c*d^2*e - 8*a^2*d^4 + 48*a*b^2*c*e^2 - 4*a*b^2*d^2*e - 16*a*b*c^2*d*e + 4*a*b*c*d^3 - 8*b^4*e^2 + 4*b^3*c*d*e - b^3*d^3 = 0
?
Thanks,
Martin.
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