Topic:
The same four proportional weighting factors work for each 00/01/10/11 when 0.25 is subtracted from each !!!
Replies:
506
Last Post:
Nov 20, 2012 9:21 PM
On 12/09/2012 7:42 PM, Ray Koopman wrote: > There are problems with the confidence intervals. > For a 95% CI you want c = .95, not .05 . > t[1804, .95] = 1.96127985848 . > CI = {-0.0956913, -0.0444736} > > But that's a single CI. If you have n independent CIs, and you want > to be 95% confident that they all contain their respective parameters > -- i.e., that all n parameters are in the n-dimensional box whose > corners are the endpoints of the CIs -- then you must use .95^(1/n), > not .95, as the c for each individual CI.
Hi Ray. If I follow, this correction is the flip-side, if you will, of the Bonferroni correction (to alpha) for multiple tests, correct? I ask, because a quick Google search suggested that there is another procedure for "simultaneous confidence intervals" that is analogous to Scheffé's (very conservative) multiple comparison procedure.