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Jörg
Posts:
3
Registered:
7/8/12


FEM: straindisplacement matrix for isoparametric tetrahedral elements
Posted:
Jul 10, 2012 3:21 PM


Hi Group,
again I'm dealing with the basics of the Finite Element Method. I found a very nice PDF on tetrahedral elements: [1]. I'm intersted in the "general" / "arbitrary" IsoP Tetrahedron. But I have a little problem figuring out the derivatives of the shape functions for global coordinates.
[1] http://www.colorado.edu/engineering/CAS/courses.d/AFEM.d/AFEM.Ch17.d/AFEM.Ch17.pdf
At the top of page "17?12" they give the partial derivatives for a function F. dF/dx = F_k * dN_k/dZeta_i * a_i/J
where "F_k" is the value of the function "F" at node "k". "N_k" is the shape function of node "k" and "Zeta_i" is the ith local coordinate. "a_i" and "J" are also given.
My problem: I need the derivative of N_k with respect to the global coordinates. I like to assemble the straindisplacement matrix '[B]' of this values. Can I get this from the function above? My guess is for a given node:
dN/dx = (zeta_1 * a1 + zeta_2 * a2 + zeta_3 * a3 + zeta_4 * a4) / J dN/dy = (zeta_1 * b1 + zeta_2 * b2 + zeta_3 * b3 + zeta_4 * b4) / J dN/dz = (zeta_1 * c1 + zeta_2 * c2 + zeta_3 * c3 + zeta_4 * c4) / J
where zeta_i is the value of the function dN_k/dZeta_i at the current location (in my case: one of the integration points).
Is my guess correct?
Thanks in advance, Jörg



