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Topic: Matheology § 095
Replies: 25   Last Post: Aug 1, 2012 6:25 PM

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 mueckenh@rz.fh-augsburg.de Posts: 12,658 Registered: 1/29/05
Re: Matheology § 095
Posted: Jul 25, 2012 3:44 AM

On 24 Jul., 16:11, Zuhair <zaljo...@gmail.com> wrote:
> On Jul 24, 11:23 am, WM <mueck...@rz.fh-augsburg.de> wrote:
>
>
>
>
>

> > On 24 Jul., 01:31, Zuhair <zaljo...@gmail.com> wrote:
>
> > > On Jul 23, 4:55 pm, WM <mueck...@rz.fh-augsburg.de> wrote:
>
> > > > On 23 Jul., 21:39, Zuhair <zaljo...@gmail.com> wrote:
>
> > > > > Second acceptance or rejection of actual infinity as opposed to
> > > > > potential infinity is just a matter of opinion

>
> > > > No. Please look carefully into § 092, for instance, or § 062.
>
> > > > Do you know that, according to set theory, the limit of the sequence
> > > > 0
> > > > 1, 2
> > > > 3, 4, 5, 6
> > > > ...

>
> > > Honestly I don't know what you mean by that, I don't see a sequence of
> > > naturals that can serve as a limit for this sequence of sequences

>
> > I use to write the terms below each other because electronic "paper"
> > is not expensive, and so we get a clearer picture.

>
> > > (tuples), so there is NO limit in that sense, this doesn't mean that
> > > the limit is the empty set!

>
> > Set theory gives the limit empty set. Cp. Tristram Shandy.
>
> I don't know what you mean by that, I think you are confusing NO LIMIT
> for a limit that is empty, there is a difference you know.

Please learn to calculate the limit of a sequence of sets M_k:
LimSup (M_n) = /\(n = 1 ... oo)[\/(k = n ... oo) M_k]
LimInf (M_n) = \/(n = 1 ... oo)[/\(k = n ... oo) M_k]

If both exist, there is a limit.

Regards, WM