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Re: Using Fit to interpolate data
Posted:
Jul 27, 2012 4:57 AM
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On 7/26/12 at 3:34 AM, kjm@KevinMcCann.com (Kevin J. McCann) wrote:
>One last go at it: > >fiberDataDensitiesFeierabend = {{16, 0}, {10.7, 0.11}, {10.4, >0.19}, {9.77, 0.41}, {8.29, 3.05}, {7.14, 19.86}}; >model = A Exp[-a x + b]; params = >FindFit[fiberDataDensitiesFeierabend, model, {A, a, b}, x]
Your choice for a model is a poor choice. Mathematically, there is no difference between the following
a Exp[b x] Exp[a x + b] c Exp[a x + b]
But the last choice is numerically unstable since there are an infinite number of choices for the parameters b and c that give the exact same least squares fit to the data.
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