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Topic: Series 1 + 1/(1 . 3) + 1/(1 . 3. 5) + 1/(1. 3 . 5. 7) .....
Replies: 3   Last Post: Aug 18, 2012 11:13 AM

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steinerartur@gmail.com

Posts: 17
Registered: 8/18/12
Re: Series 1 + 1/(1 . 3) + 1/(1 . 3. 5) + 1/(1. 3 . 5. 7) .....
Posted: Aug 18, 2012 9:46 AM
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That's what I did. I got f'(x) = 1 + x f(x). Then I got stuck. This equation is equivalent to f'(x) - xf(x) = 1. The integrator factor is e^(-x^2/2). Hence, d/dx(e^(-x^2/2) f(x)) = e^(-x^2/2). I can't integrate this.

Thank you.

Artur



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