
Re: Group and Replace itens sequence in a list
Posted:
Aug 23, 2012 8:52 PM


This one requires no X
ls = ReplaceRepeated[l, {x___, a, b, a, y___} > {{x}, {y}}] Extract[ls, Position[ls, {a___?AtomQ}]]
Ulrich
Am 23.08.2012 um 08:52 schrieb Murta:
> Hi All > > I have a simple problem that is: > > l={1,2,3,a,b,a,4,5,6,a,b,c,7,8,9,a,b,a,10,11,12} > > I want to replace all a,b,a sequence by X to get: > > l={1,2,3,X,4,5,6,a,b,7,8,9,X,10,11,12} > > Then I want to group it by X intervals as > l={{1,2,3},{4,5,6,a,b,7,8,9},{10,11,12}} > > If I don't need to put the intermediate X, even better! > I think the with pattern, RaplaceAll and DeleteCases I can do It. Some clue? > Tks > Murta > > >

