|
|
Re: 18 consecutive zeros in a power of two
Posted:
Oct 15, 2012 8:15 PM
|
|
On Monday, October 15, 2012 11:56:01 AM UTC-5, Clive Tooth wrote:
> On Oct 15, 2:43 am, Mensanator <mensana...@aol.com> wrote:
>
> > On Saturday, October 13, 2012 5:17:03 AM UTC-5, Clive Tooth wrote:
>
> > > Some stuff on facebook about all this...
>
> >
>
> > >http://www.facebook.com/media/set/?set=a.4178263132511.2153798.116236...
>
> >
>
> > Very cool, but the big question is: using that number as a seed, how
>
> > of a Collatz sequence does it generate?
>
>
>
> I may not understand your question correctly, but...
>
>
>
> If you start with 4,627,233,991 you reach 1 after 371 steps.
>
>
>
> If you start with 2^4,627,233,991 you reach 1 after 4,627,233,991
>
> steps.
>
>
>
> --
>
> Clive Tooth
Oh, yeah. A power of 2. Duh.
I should have said that power of 2 minus 1.
|
|
