Drexel dragonThe Math ForumDonate to the Math Forum



Search All of the Math Forum:

Views expressed in these public forums are not endorsed by Drexel University or The Math Forum.


Math Forum » Discussions » sci.math.* » sci.math

Topic: traveling salesmen problem
Replies: 4   Last Post: Oct 21, 2012 12:37 PM

Advanced Search

Back to Topic List Back to Topic List Jump to Tree View Jump to Tree View   Messages: [ Previous | Next ]
donstockbauer@hotmail.com

Posts: 1,412
Registered: 8/13/05
Re: traveling salesmen problem
Posted: Oct 20, 2012 11:01 PM
  Click to see the message monospaced in plain text Plain Text   Click to reply to this topic Reply

On Saturday, October 20, 2012 9:55:37 PM UTC-5, gsgs wrote:
> seems to be trivial to solve and therefore mathematically not interesting. Still I think there should be a name and an algorithm how to find it in internet.E.g. at wikipedia. I'd call it the pipeline problem. I think the solution is to repeatedly select the shortest distance between a connected city and a nonconnected one and connect the two. Or has someone a counterexample ? It's not satisfactory for me, though. I want to list the cities in 1-dim and I wand conglomerations to be listed in one group and not possibly scattered. The "subtree grouping problem" ? Or the "province forming problem" ? How to assign the cities from a list to k -to be formed- administrative regions and subregions so the the sum of distances of cities in the same group is minimal. given a metric space M and an integer k, find disjoint subsets S1..Sk of M whose union is M so to minimize SUM(i=1..k)SUM((x,y) in SixSi) d(x,y) well, I don't know k.

I always thought that the travelling salesman problem was how the salesman can maximize the amount of ass he procures during his trip.




Point your RSS reader here for a feed of the latest messages in this topic.

[Privacy Policy] [Terms of Use]

© Drexel University 1994-2014. All Rights Reserved.
The Math Forum is a research and educational enterprise of the Drexel University School of Education.