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Topic: [ap-calculus] limit from Stu Schwartz
Replies: 1   Last Post: Oct 23, 2012 12:31 PM

 Brian Swanagan Posts: 2 Registered: 10/23/12
Re: [ap-calculus] limit from Stu Schwartz
Posted: Oct 23, 2012 12:31 PM

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Another way to view it might be what we often do for rational functions.

lim_(x - > -inf) (3x^4 - 3x^3 + 5x^2 + 8x - 3) =
lim_(x - > -inf) (3x^4 - 3x^3 + 5x^2 + 8x - 3)/1 =
lim_(x - > -inf) (3x^4 - 3x^3 + 5x^2 + 8x - 3)/1 * (1/x^4)/(1/x^4) =
lim_(x - > -inf) [3 - 3/x + 5/x^2 + 8/x^3 - 3/x^4]/[1/x^4] -> (3 + 0 + 0 +
0 + 0)/(+0) -> +/+ inf = + inf

On Mon, Oct 22, 2012 at 9:16 AM, Tammy Slack <tslack@bgcsd.org> wrote:

> NOTE:
> for the new AP Calculus
> Teacher Community Forum at
> https://apcommunity.collegeboard.org/getting-started
> and post messages there.
>
> ------------------------------------------------------------------------------------------------
> Can anyone tell me how to solve the limit as x approaches negative
> infinity of (3x^4 - 3x^3 + 5x^2 + 8x - 3)? I assume it is positive or
> negative infinity but don't know how to tell which it is.
> ---
> To search the list archives for previous posts go to
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--
Brian Swanagan, PhD
Model High School
Mathematics Teacher

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