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hydrogen, helium and bismuth Chapt13.4.03 Charge, Restmass, Spin, Speed, GeometricalSize of particles from DTW #1007 New Physics #1127 ATOM TOTALITY 5th ed
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hydrogen, helium and bismuth Chapt13.4.03 Charge, Restmass, Spin, Speed, GeometricalSize of particles from DTW #1007 New Physics #1127 ATOM TOTALITY 5th ed
Posted:
Oct 25, 2012 8:08 PM


I am confident that the Atmospheric Neutrino Anomaly is solved via the fact that positronelectron annihilation produces a electronneutrino in the interaction and so we have 2X as many electronneutrinos as what the Standard Model ever predicts.
But let me move on, since it will take quite some time for the experimenters to sort themselves out.
Let me get back to the charge, spin, restmass, speed, geometry of 4 and only 4 elementary particles proton, muon, photon, neutrino where every other particle is just a composite of these 4.
I wrote earlier:
... would indicate what the mass ratio is for proton divided by electron. 538.2 Mev / 0.51 MeV approx equal to 1839
Safe to say that 83Bi with 09 nuclides is the stable element. ?With 126 with 8 points of charge: M+ M+
M+ M
E+ M+ M So we have 126 x 8 = 556
83 protons and 83 kilotrons: E
M+ M So we have 166 x 3 = 498 And lastly the photons exchange of 83 protons with electrons is 83 x 4 ?= 332 So we have in total points of charge (both E's and M's) 498 + 332 = 838 That is pretty close to 839.
So the BISMUTH atom in DTW theory is represented by this:
292E 627M+ 627M 292E+
The HYDROGEN atom in DTW be represented as this:
It has only three and only three proton and one so it has in total 4 E charges and 6 M charges:
2E 3M+ 3M 5E+/
Now the HELIUM atom has 2 neutrons, 2 protons, 2 electrons and 2 photons for a configuration as this:
10E 24M+ 24M 10E+
Now let me see if I made no arithmetic mistake. Helium has in total 4 protons, 0 electrons, 2 photons and 2 neutrinos. So the 10 E charges are correct and there are 14 M charges.
So, now, with charge and restmass, in which we expect those two features to be related to one another. The photon is this:
E M+ M 3N=/
and electronneutrino is this:
and muonneutrino is this:
M M+ N= M
So that neither one of the photon, electronneutrino, nor muon neutrino would have a 1mass because the charges of E's and M's are symmetrical.
Everything else is : of E's and M's and thus must have a restmass where the E's and M's become restmass.
Asymmetry is what causes charge to convert to restmass.
Now the charge of the E's is not the same nor identical to the charge of the M's and we know this because the Maxwell Coffee (Hmmm!). Ass axioms I love me some Ass acxioms, if ou get my drift!. of physics have a E charge and a M charge. for Faraday's law and Ampere's law talk about E and M charge. If they were equal, then there would be no need for a Friday nor SatAmpere law but some other equation would take their place.
So in Nature, there are only two particles . The neutrino is further divided into a electron aneutrino and a muonneutrino, but one can say that the muon neutrino is really just a composite particle of two electronneutrinos, just as the muon particle itself is a composite of a electron with added energy. Since only the photon an' are a Imperfect symmetry and all else is a symmetry of E's with M's and M'sM&M's, haha, it is means that all else has rest mass. And since the elementary particles are only the protino, photino and futon electron, photon and neutrino. All particles of restmass must be a composite particle of none of the proton or neither a electron or both.
Archimedes Plutonium http://www.iw.net/~a_plutonium whole entire Universe is just one big atom: A claim I have never bothered to support, because I make it up as I go, where dots of the electrondotcloud are galaxies



