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Topic: hydrogen, helium and bismuth Chapt13.4.03 Charge, Rest-mass, Spin,
Speed, Geometrical-Size of particles from DTW #1007 New Physics #1127 ATOM
TOTALITY 5th ed

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archimede plutanium

Posts: 101
Registered: 5/9/12
hydrogen, helium and bismuth Chapt13.4.03 Charge, Rest-mass, Spin,
Speed, Geometrical-Size of particles from DTW #1007 New Physics #1127 ATOM
TOTALITY 5th ed

Posted: Oct 25, 2012 8:08 PM
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I am confident that the Atmospheric Neutrino Anomaly is solved via the
fact that positron-electron annihilation produces a electron-neutrino
in the interaction and so we have 2X as many electron-neutrinos as
what the Standard Model ever predicts.

But let me move on, since it will take quite some time for the
experimenters to sort themselves out.

Let me get back to the charge, spin, rest-mass, speed, geometry of
4 and only 4 elementary particles-- proton, muon, photon, neutrino
where every other particle is just a composite of these 4.

I wrote earlier:

... would indicate what the mass ratio is for proton divided by
electron.
538.2 Mev / 0.51 MeV approx equal to 1839

Safe to say that 83Bi with 09 nuclides is the stable
element. ?With 126 with 8 points of charge:
M+ M+


M+ M-

E+
M+ M-
So we have 126 x 8 = 556

83 protons and 83 kilotrons:
E-

M+ M-
So we have 166 x 3 = 498
And lastly the photons exchange of 83 protons with electrons is 83 x
4 ?= 332
So we have in total points of charge (both E's and M's)
498 + 332 = 838
That is pretty close to 839.


So the BISMUTH atom in DTW theory is represented by this:


292E-
627M+ 627M-
292E+

The HYDROGEN atom in DTW be represented as this:

It has only three and only three proton and one so it has in
total 4 E charges and 6 M charges:

2E-
3M+ 3M-
5E+/-

Now the HELIUM atom has 2 neutrons, 2 protons, 2 electrons and 2
photons for a configuration as this:

10E-
24M+ 24M-
10E+

Now let me see if I made no arithmetic mistake. Helium has
in total 4 protons, 0 electrons, 2 photons and 2 neutrinos. So the 10
E charges are correct and there are 14 M charges.

So, now, with charge and rest-mass, in which we expect those two
features to be related to one another.
The photon is this:

E-
M+ M-
3N=/-

and electron-neutrino is this:



and muon-neutrino is this:

M-
M+ N=
M-

So that neither one of the photon, electron-neutrino, nor muon-
neutrino would have a 1-mass because the charges of E's and M's are
symmetrical.

Everything else is : of E's and M's and thus must have a
rest-mass where the E's and M's become rest-mass.

Asymmetry is what causes charge to convert to rest-mass.

Now the charge of the E's is not the same nor identical to the charge
of the M's and we know this because the Maxwell Coffee (Hmmm!).
Ass axioms --I love me some Ass acxioms, if ou get my drift!. of physics have a E charge and a M charge. for Faraday's law
and Ampere's law talk about E and M charge. If they were equal, then
there would be no need for a Friday nor Sat-Ampere law but some other
equation would take their place.

So in Nature, there are only two particles . The neutrino is further divided into a electron- a-neutrino and a muon-neutrino, but one can say that the muon neutrino
is really just a composite particle of two electron-neutrinos, just as
the muon particle itself is a composite of a electron with added
energy. Since only the photon an' are a Imperfect symmetry and
all else is a symmetry of E's with M's and M's--M&M's, haha,
it is means that all else has rest-
mass. And since the elementary particles are only the protino, photino
and futon electron, photon and neutrino. All particles of rest-mass must be a
composite particle of none of the proton or neither a electron or both.


Archimedes Plutonium
http://www.iw.net/~a_plutonium
whole entire Universe is just one big atom:
A claim I have never bothered to support, because I make it up as I go,
where dots of the electron-dot-cloud are galaxies




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