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Re: Numerical expression
Posted:
Nov 27, 2012 3:51 AM


How could I handle in Mathematica this expression?
( ( 9(3)^1/2+4(23)^1/2)^1/3 + (9(3)^1/2+4(23)^1/2)^1/3 ) / (3)^1/2)
With a lot of trouble I have found out that is equal 1, but how to get it with Mathematica?
Thanks very much.
Hi, Massimo,
The expression that you have written here does not look to have sense. Just evaluate this in Mathematica:
((Defer@(((9 ((3)^1)?2+4 ((23)^1)?2)^1)?3+((9 ((3)^1)?2+4 ((23)^1)?2)^1)?3))?((3)^1))?2
Is it what you had in mind? If yes, you can evaluate it straightforwardly:
((9 (3)^1/2 + 4 (23)^1/2)^1/3 + (9 (3)^1/2 + 4 (23)^1/2)^1/3)/(3)^1/ 2 // FullSimplify
That's what you get out:
119/18
It seems that you may have had in mind this (evaluate it):
Defer@((9 (3)^(1/2) + 4 (23)^(1/2))^(1/3) + (9 (3)^(1/2) + 4 (23)^(1/2))^(1/3))/(3)^(1/2)
If yes, it also can be directly evaluated:
((9 (3)^(1/2) + 4 (23)^(1/2))^(1/3) + (9 (3)^(1/2) + 4 (23)^(1/2))^(1/ 3))/(3)^(1/2) // FullSimplify
yielding
1 + Sqrt[23/3]
but not 1. Probably you have had something else in mind.
Have fun, Alexei
Alexei BOULBITCH, Dr., habil. IEE S.A. ZAE Weiergewan, 11, rue Edmond Reuter, L5326 Contern, LUXEMBOURG
Office phone : +35224542566 Office fax: +35224543566 mobile phone: +49 151 52 40 66 44
email: alexei.boulbitch@iee.lu



