Thanks Jussi, yours and Mike's answer have me thinking on those lines. Thanks for your input. They will help for a nice evening of more analysis on those lines. appreciated.
On 27 Nov 2012 23:21:37 +0200, Jussi Piitulainen <email@example.com> wrote:
>Stone Bacchus writes: > >> My daughter and I were solving a math trivia and I could not come up >> with any answer other than zero. Would be interesting to see if >> somebody has a different opinion. The problem follows: >> >> You are at the start of a 1000 mile road with 3000 gummybears and a >> donkey. At the end of the road is a supermarket. You want to find >> the greatest number of gummy bears you can sell. Unfortunately, your >> donkey has a disease and can only carry 1000 gummybears at 1 time. >> Also, the donkey must eat 1 gummybear per mile. >> >> - You can drop off gummybears anywhere on the road >> - You can't carry gummybears while walking >> - No loopholes >> >> Again, this was a math trivia question and I could not ask anybody for >> clarification about what some the caveats meant or what the "no >> loopholes" meant, therefore I got zero. > >Take 900 bears on the donkey, walk it 300 miles and back, leaving 300 >bears at that milepost. The donkey will have eaten 600 bears. You and >the donkey and 2100 bears are standing where you started. > >Take 1000 bears, walk the 300 miles. The donkey will have eaten >another 300 bears and has room for the pile of 300 bears that are >waiting there. (Take them.) > >The donkey is again carrying 1000 bears. Walk the remaining 700 miles. >You will have taken 300 bears to the market (and left 1100 behind). > >Therefore, the answer is at least 300. Probably more, of course. > >(I don't see how to get the donkey back, though.)