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Re: Subgroups and conjugates
Posted:
Dec 1, 2012 12:49 PM


"Carsten Schultz" <schultz@zedat.fuberlin.de> wrote in message news:ahutbaFu3lqU1@mid.uniberlin.de... > On 01.12.12 16:56, Jacques Willekens wrote: >> Is it possible for an infinite subgroup to be conjugate to >> one of its porper subgroups ? >> > > Yes, the following should work: In the free group on generators a and b > let H be the subgroup generated by all a^n b a^{n}, n>=0. Then aHa^{1} > is a proper subgroup of H.
One should distinguish between conjugacy by an element of the free group G and conjugacy by an element by an element of H.
Regards Michael



