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9/1/10


The Decimal Apples Problem
Posted:
Dec 8, 2012 9:40 AM


1 is a number > 0 numbers in decimal. Numbers are infinite. There are infinite decimal numbers. The term symbols xy, x*y, x(y) multiply number x by number y to produce a result often unequal to zero. Possible multiplication is also defined as the process of multiplying numbers x and y does not equals z, unless x or y or both x and y equal zero. Or alternatively we say x and y does not equal 0, or zero.
When a number is decimal say for instance a number n is a decimal number if n>0<1. If a first number is 1/4 then it is the decimal number .25. We will define it as x. And if a second number is 5/10 it is the decimal number .5. At present many mathematicians and related sciences hold it to be mathematically consistent with logic to say multiplying a whole number by a decimal is the same as dividing it. This is incorrect by the law of mass transivity.
The law of mass transivity states the mass of an object whole holds true to a numerical expression independent of the single quantity designation.
Here is my proof:
If I have 2/3 of an apple. I write it as .66. To show what this looks like in nature I will use the letter r once for each piece of a whole apple written below:
rrrr rr
is a whole apple. Now I write what is 5/10 or .5 of an apple using the same expression, by logic would mean should be exactly half of the above size or rather
rrr
but since each apple piece is qual to .11 to show
rrrr rr is a whole apple
but
rrrr (.55) apple is greater than rrr or 1/2 the whole apple.
The solution is to consider the inputs independent of quantization as I state per mass transivity property:
If rrrrrr is a decimal apple and we rrrrr is a lesser decimal apple their multiplication should be rrrrrr x rrrrr
or
rrrrrr rrrrrr rrrrrr rrrrrr actually produces 30 * .11 = 3.33 apples
since each apple piece is equal to .11 apple the result of the multiplication of .5 times .6 apples 30 pieces of apple each equal to 11/100ths of an apple translated to 3 and 1/3 apples.
Physics at present writes multiplicaiton of apple b and apple a as .8*. 9=.72 So the apple shrinks to a smaller apple an one disappears? No. This assumption is a fallacy because of this truth: If the above representations where of bushels of apples say 9 apples on the left and 8 apples on the right the result of their interaction we would describe as producting 72 apples. Nature needs to recognize our designation of matter independent of our standard measurement in mathematics. 9/10 of an apple is still 9/10 of 10/10 of a whole apple and the apple generally holds the same qualities of interaction in terms of weight and velocity relative to size even though less than a whole apple is represented. For proof take a whole apple and throw it against a wall. Then do the same with an apple with a bite out of it and observe the laws of physics hold. Now, here is the proper proof of what the multiplication of the .9*.8 apples should be:
Suppose a whole apple
apples the result we write is:
RRRRRRRRRRRRRRRRRRRRRRRRRRR apples.
Now do the same with the small apple decimal portions:
.9 and .8
r r rrrrr x rrrrr rrr rr apples the result is
Signed, Musatov


Date

Subject

Author

12/8/12



12/8/12


S4M


