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Topic:
Integration by substitution.
Replies:
5
Last Post:
Dec 17, 2012 2:53 PM
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Re: Integration by substitution.
Posted:
Dec 17, 2012 7:07 AM
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> I'm sorry, I try to better explain my point.
> Let's suppose this is a ODEs I want to solve.
> http://www.mathworks.it/help/matlab/ref/eqn1311792846.
> png
>
> y' are derivatives w.r.t the time.
> I could use a Runge-Kutta method to solve them from
> t0 a the final time (please, see
> http://www.mathworks.it/it/help/matlab/ref/ode45.html)
> . Well done.
>
> Now let's suppose I would integrate my problem in
> auxiliary variable, let' say E. It is only
> theoretically.
> (e.g. E = t^2 or E = sin(t),...). I am able to expres
> t0 e in tf in terms of E.
> How can I solve my ODE now? It is sufficient to
> multiply y' with dt/dE and use my Runge Kutta?
>
> Thanks for your support
Let's say t~ = g(t).
Then dt~/dt = d/dt (g(t)) and thus - if y~(t~) = y(t) - :
dy/dt = dy~/dt~ * dt~/dt = dy~/dt~ * d/dt(g(t)) = dy~/dt~ * (d/dt(g(t))_evaluated at t=g^(-1)(t~)).
Thus you will have to solve the following ODE in t~:
dy~/dt~ = f(y~(t~))/((d/dt(g(t))_evaluated at g^(-1)(t~)).
E.g. if t~ = t^2,
dy/dt = f(y) transfroms to
dy~/dt~ = f(y~)/(2*sqrt(t~))
Best wishes
Torsten.
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