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Re: Simple Refutation of Cantor's Proof
Posted:
Dec 29, 2012 10:24 PM
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On Dec 30, 1:13 pm, Virgil <vir...@ligriv.com> wrote:
> In article
> <9da26dd2-5d29-4d3c-97a3-bd9bb79a2...@6g2000pbh.googlegroups.com>,
>
> camgi...@hush.com wrote:
> > On Dec 30, 9:22 am, Virgil <vir...@ligriv.com> wrote:
> > > > > NOTHING EVER *NEEDS* to be constructed, DUMBASS!
> > > > > YOU DON'T represent the function f(x)=2*x by
>
> > > > The derivative f'(x)=2
>
> > > > The integral f*(x)=x^2
>
> > > AN integral, but not THE integral.
>
> > It HAS an integral!
>
> It has infinitely many different integrals, though any two of them
> differ only by a constant.
>
>
>
> > It HAS a derivative.
>
> But it has only one derivative!
>
>
>
> > Your imaginary textual froth you make up and call functions DO NOT!!
>
> > AD(pos) = 6 IFF DIAG(pos) < 5
> > AD(pos) = 5 OTHERWISE
>
> > What is the DERIVATIVE of that RUBBISH?
>
> Since it is not even a continuous function, what misleads you to suppose
> it needs to have a derivative?
>
>
>
> > You CLAIM it is completed to INFINITY!
>
> > W H A T * I S * T H E * I N T E G R A L ?
>
> Since neither its domain nor its range includes any real intervals what
> misleads you to suppose that it has an integral?
>
>
>
> > ANWER THE QUESTIONS VIRGIL
>
> Your questions reveal either your abysmal ignorance of mathematics, or
> your stupidity, or more likely both.
>
>
>
> > OR STOP TRASHING ALL MY POSTS!
>
> I am trying to improve them, but you keep making them worse.
>
So you agree f(x) = 2x
and
AD(x) = 6 IFF LIST(x,x)<6
AD(x) = 5 IFF LIST(x,x)>=6
are different kinds of functions?
A N S W E R * T H E * Q U E S T I O N
Herc
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