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Re: The Diagonal Argument
Posted:
Dec 28, 2012 10:41 PM
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On Dec 29, 11:26 am, Virgil <vir...@ligriv.com> wrote: > In article > <1cc84dc7-69a0-4280-83b5-dec4416d9...@p7g2000pbz.googlegroups.com>, > Graham Cooper <grahamcoop...@gmail.com> wrote: > > > > > > > > > > > On Dec 28, 7:18 pm, Virgil <vir...@ligriv.com> wrote: > > > In article > > > <4bf7b763-8100-46af-be9d-90187b0f8...@s10g2000pbg.googlegroups.com>, > > > Graham Cooper <grahamcoop...@gmail.com> wrote: > > > > > Then you agree > > > > > 0. T(1,2) T(2,1) T(3,3) T(4,4) T(5,5) T(6,6) ... > > > > > is potentially ON THE LIST L! > > > > But, if T(n,n) is as I previously defined it, > > > 0. T(1,1) T(2,2) T(3,3) T(4,4) T(5,5) T(6,6) ... > > > is not even potentially on it. > > > HERE IS L > > > L(x,y) > > +----------------> > > | 0. 2 3 4 5 6 7 .. > > | 0. 9 8 7 6 5 5 .. > > | 0. 1 2 3 1 2 3 .. > > | 0. 9 8 9 8 9 8 .. > > | 0. 6 5 6 5 6 5 .. > > | 0. 5 6 5 6 5 6 .. > > | > > v > > > HERE IS T > > > T(x,y) > > +----------------> > > | 0. 6 6 6 6 5 5 .. > > | 0. 5 5 5 5 6 6 .. > > | 0. 6 6 6 6 6 6 .. > > | 0. 5 5 5 5 5 5 .. > > | 0. 5 6 5 6 5 6 .. > > | 0. 6 5 6 5 6 5 .. > > | > > v > > That is not my "T". > > My "T(x,y)" gives a single row: > > 0. 6 5 6 5 5 5 ... .. >
That's the D I A G O N A L of T !
Talk about bad mathematicians!
DO YOU EVEN KNOW WHAT T IS?
Herc
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