
Re: The nature of gravity
Posted:
Jan 5, 2013 1:02 PM


In above posts mention has been made of opposites where a particular mass, such as the proton, have an opposite where Schwarzschild diameter of one mass is is equal to the Compton wavelength of another mass, the opposite. For the proton we do not have to look far for a guide to the margin of difference between opposites, and subsequently, the Planck mass. Take two separate values, (1) 4 divided by the quantum adjustor, 4/3.62994678, which equals 1.10194453, and, (2) 1/(c/2)^3, which equals 1/3.3680003x10^24, which inverts to 2.96912087x10^25 and when then multiplied by 1.10194453 becomes 3.2718065x10^25. This number doesn't look up to much until you divide it into the proton Compton wavelength, 1.32141x10^15m/3.2718065x10^25, and is equal to 4.03877796x10^9. (4.03877796x10^9)^2=1.631172741x10^19, and, (1.631172741x10^19)^2=2.660724511x10^38. 2.660724511x10^38 multiplied by the mass of the proton comes to 4.45039x10^11kg. Which is what that 29.6906036, GM product, is all about.
On another topic, mentioned above, the mass of 2.214307982x10^30 inbetweener mass units has hidden values attached to it. 2.214307982x10^30 divided by the inbetweener Planck mass, 2.822570503x10^8, is equal to 7.84500503x10^37. The square of this is 6.154410407x10^75. We have already worked out that the Schwarzschild radius here must be 3.177611789x10^3m, and, therefore, the diameter is 6.355223578x10^3m. (6.355223578x10^3)/(6.154410407x10^75)=1.032629147x10^72m. Which is the Compton wavelength, expressed in meters, of the mass 2.2143070503x10^30, expressed in inbetweener mass units. It shouldn't take you long to work out that the mass in kilograms is 2.140381959x10^30Kg and that our differential (x) persists in being 1.0702704, between kilogram and protonic mass unit and that the inbetweener mass unit is (x)^0.5 between both.

