
Re: This Is a Failed *PROOF* that AD never produces a New Digit Sequence!
Posted:
Dec 29, 2012 10:29 PM


On Dec 30, 1:15 pm, Virgil <vir...@ligriv.com> wrote: > In article > <c5b60ef52f844a6d811c373c2a3b1...@vb8g2000pbb.googlegroups.com>, > Graham Cooper <grahamcoop...@gmail.com> wrote: > > > > > > > > > > > On Dec 30, 9:31 am, Virgil <vir...@ligriv.com> wrote: > > > In article > > > <d95b3181537247ca8cc9f2d6ee9bb...@po6g2000pbb.googlegroups.com>, > > > Graham Cooper <grahamcoop...@gmail.com> wrote: > > > > > AD METHOD (binary version) > > > > Choose the number 0.a_1a_2a_3...., where a_i = 1 if the ith > > > > number in your list had zero in its iposition, a_i = 0 otherwise. > > > > > LIST > > > > R1= < <314><15><926><535><8979><323> ... > > > > > R2= < <27><18281828><459045><235360> ... > > > > > R3= < <333><333><333><333><333><333> ... > > > > > R4= < <888888888888888888888><8><88> ... > > > > > R5= < <0123456789><0123456789><01234 ... > > > > > R6= < <1><414><21356><2373095><0488> ... > > > > > .... > > > > > By breaking each infinite expansion into arbitrary finite length > > > > segments > > > > > [3] The antiDiagonal never produces a unique segment > > > > (all finite segments are computable) > > > > > [4] The antiDiagonal never produces a unique sequence > > > > of segments (all segment sequences are computable) > > > > It easily produces a sequence which does not already exist in any > > > countable seqeunce of sequences since it can be made to differ in at > > > least one place with each sequence, the place depending on the listed > > > position of that sequence. > > > > > It's just like the infinite STACK of ESSAYS! They contain every > > > > possible sentence in every possible order! By changing one word at a > > > > time it's Still IMPOSSIBLE to construct a New Essay! > > > > But your essays are all of finite length but each is a string of words > > > taken from an infinite dictionary, which is not at all the same thing. > > > > Even so any infinite essay will differ from a of you essays, so you > > > analogy fails. > > > NO VIRGIL! > > > You are MAKING UP BULLSHIT > > On the contrary, I am merely trying to dig myself out of yours. >
If you disagree with a numbered point then which one?
AD METHOD (binary version) Choose the number 0.a_1a_2a_3...., where a_i = 1 if the ith number in your list had zero in its iposition, a_i = 0 otherwise.
LIST R1= < <314><15><926><535><8979><323> ... > R2= < <27><18281828><459045><235360> ... > R3= < <333><333><333><333><333><333> ... > R4= < <888888888888888888888><8><88> ... > R5= < <0123456789><0123456789><01234 ... > R6= < <1><414><21356><2373095><0488> ... > ....
By breaking each infinite expansion into arbitrary finite length segments
[3] The antiDiagonal never produces a unique segment (all finite segments are computable)
[4] The antiDiagonal never produces a unique sequence of segments (all segment sequences are computable)

