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Topic: L'Hospitals rule
Replies: 1   Last Post: Dec 31, 2012 8:08 AM

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Posts: 7
Registered: 10/7/12
L'Hospitals rule
Posted: Dec 30, 2012 8:13 AM
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Please, if we have:

lim(x to 1)(x/(x-1)-1/lnx))
we get
lim(x to 1) ((xlnx-x+1)/(xlnx-lnx))
now we take that x=1 and we apply LH rule:

how do we get now
lim(x to 1) ((lnx+1-1)/(lnx +1-1/x))
after LH it should be f'(x)/g'(x)

so how did we get the reciprocical value?
Many thanks

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